AP EAMCET · Maths · Quadratic Equation
For any real value of \(x\), if \(\frac{11 x^2+12 x+6}{x^2+4 x+2} \notin(a, b]\) then the value x for which \(\frac{11 x^2+12 x+6}{x^2+4 x+2}=b-a+3\) is
- A \(\frac{3}{4}\)
- B \(\frac{3}{2}\)
- C 2
- D \(-\frac{1}{2}\)
Answer & Solution
Correct Answer
(D) \(-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\frac{11 x^2+12 x+6}{x^2+4 x+2}=y\)…
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