AP EAMCET · Maths · Circle
The equation of the circle which cuts the circles \(x^2+y^2+4 x-7=0\), \(2 x^2+2 y^2+3 x+5 y-9=0, x^2+y^2+y=0\) orthogonally is
- A \(x^2+y^2-4 x-2 y-1=0\)
- B \(x^2+y^2-4 x-6 y-3=0\)
- C \(x^2+y^2-4 x-2 y-3=0\)
- D \(x^2+y^2-2 x-4 y-1=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2-4 x-2 y-1=0\)
Step-by-step Solution
Detailed explanation
The centre of the circle which cuts the given circles having equation \[ \begin{aligned} & S_1: x^2+y^2+4 y-7=0 \\ & S_2: 2 x^2+2 y^2+3 x+5 y-9=0 \end{aligned} \] and \(S_3: x^2+y^2+y=0\) is radical centre of circles \(S_1, S_2\) and \(S_3\). \(\because\) Equation of radical…
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