AP EAMCET · Maths · Probability
If \(\mathrm{X}\) is a random variable such that \(P(X=-2)=P(X=-1)=P(X=2)=P(X=1)=\frac{1}{6}\) and \(P(X=0)=\frac{1}{3}\), then the mean of \(X\) is
- A \(\frac{5}{3}\)
- B 1
- C 0
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(C) 0
Step-by-step Solution
Detailed explanation
\(p(X=-2)=p(X=-1)=p(X=2)=p(X=1)=\frac{1}{6}\)…
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