AP EAMCET · Maths · Application of Derivatives
Find the coordinates of a point on the curve \(y=x^2-3 x+2\), at which the tangent drawn to this curve is perpendicular to the line \(y=x\).
- A \((0,2)\)
- B \((1,0)\)
- C \((-1,6)\)
- D \((2,-3)\)
Answer & Solution
Correct Answer
(B) \((1,0)\)
Step-by-step Solution
Detailed explanation
Given curve, \(y=x^2-3 x+2\) On differentiating w.r.t. \(x\), \(\frac{d y}{d x}=2 x-3\) Which represents the slope of tangent drawn to the curve. \(m_1=2 x-3\) ...(i) Given line, \(\quad y=x\) ...(ii) On comparing with \(y=m x+c\) Slope of line (ii), \(m_2=1\) \(\therefore\)…
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