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AP EAMCET · Chemistry · Chemical Kinetics

If the rate constant of a first order reaction is \(4.606 \times 10^{-3} \mathrm{~s}^{-1}\), then find the time required for \(400 \mathrm{~g}\) of the reactant to reduce to \(50 \mathrm{~g}\).

  1. A 7.52 min
  2. B 0.45 min
  3. C 46.06 min
  4. D 15.05 min
Verified Solution

Answer & Solution

Correct Answer

(A) 7.52 min

Step-by-step Solution

Detailed explanation

Given, Rate constant, \(k=4.606 \times 10^{-3} \mathrm{~s}^{-1}\) Concentration at, time \(t=50 \mathrm{~g}\) Initial concentration \(=400 \mathrm{~g}\) Now, formula,…