ExamBro
ExamBro
AP EAMCET · Chemistry · States of Matter

At \(300 \mathrm{~K}\), the compressibility factor of 1 mole of a gas is 1.1. Its pressure is \(2.706 \mathrm{~atm}\). What is its volume in \(\mathrm{L}\) ? \(\left(\right.\) Given \(\left.\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\).

  1. A \(1\)
  2. B \(10\)
  3. C \(100\)
  4. D \(0.1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & Z=\frac{P V}{R T} \Rightarrow V=\frac{Z R T}{P}=\frac{(1.1)(0.082)(300)}{2.706} \\ & =10 L\end{aligned}\)