AP EAMCET · Maths · Continuity and Differentiability
Let \(f: R \rightarrow R\) be defined by
\(f(x)=\left\{\begin{array}{ccc}\alpha+\frac{\sin [x]}{x}, & \text { if } & x>0 \\ 2, & \text { if } & x=0 \\ \beta+\left[\frac{\sin x-x}{x^3}\right], & \text { if } & x < 0\end{array}\right.\)
where, \([x]\) denotes the integral part of \(x\). If \(f\) continuous at \(x=0\), then \(\beta-\alpha\) is equal to
- A \(-1\)
- B \(1\)
- C \(0\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(1\)
Step-by-step Solution
Detailed explanation
Given. \(f(x)=\left\{\begin{array}{lll}\alpha+\frac{\sin [x]}{x}, & \text { if } & x>0 \\ 2, & \text { if } & x=0 \\ \beta+\left[\frac{\sin x-x}{x^3}\right], & \text { if } & x < 0\end{array}\right.\) Since, \(f\) is continuous at \(x=0\). \(\therefore \mathrm{IHI}=f(0)=\) RHI.…
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