AP EAMCET · Maths · Definite Integration
\[
\int e^x\left(\frac{2+\sin 2 x}{1+\cos 2 x}\right) d x=
\]
- A \(e^x \sec x+C\)
- B \(\mathrm{e}^{\mathrm{x}} \tan \mathrm{x}+\mathrm{C}\)
- C \(\mathrm{e}^{\mathrm{x}} \cot \mathrm{x}+\mathrm{C}\)
- D \(\mathrm{e}^{\mathrm{x}} \operatorname{cosec} \mathrm{x}+\mathrm{C}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{e}^{\mathrm{x}} \tan \mathrm{x}+\mathrm{C}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Let } I=\int e^x\left(\frac{2+\sin 2 x}{1+\cos 2 x}\right) d x \\ & =\int e^x\left(\frac{2+\sin 2 x}{2 \cos ^2 x}\right) d x \\ & =\int e^x \sec ^2 x d x+\int e^x \tan x d x \\ & =\left[e^x \int \sec ^2 d x-\int e^x \tan x d x\right]+\int e^x \tan x d…
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