AP EAMCET · Maths · Circle
The equation of the circle passing through the points of intersection of the circles \(x^2+y^2-2 p x=0\) and \(x^2+y^2-2 q y=0\) and having its centre on \(\frac{x}{p}-\frac{y}{q}=2\), is
- A \(x^2+y^2+3 p x+q y=0\)
- B \(x^2+y^2+p x-q y=0\)
- C \(x^2+y^2-3 p x+q y=0\)
- D \(x^2+y^2-4 p x+2 q y=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-3 p x+q y=0\)
Step-by-step Solution
Detailed explanation
\((x^2+y^2-2 p x) + \lambda (x^2+y^2-2 q y) = 0\) Center: \(C \equiv \left(\frac{p}{1+\lambda}, \frac{\lambda q}{1+\lambda}\right)\) \(\frac{\frac{p}{1+\lambda}}{p} - \frac{\frac{\lambda q}{1+\lambda}}{q} = 2\) \(\frac{1}{1+\lambda} - \frac{\lambda}{1+\lambda} = 2\)…
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