AP EAMCET · Maths · Trigonometric Equations
If \(\frac{1}{6} \sin \theta, \cos \theta\) and \(\tan \theta\) are in geometric progression, then the solution set of \(\theta\) is
- A \(2 n \pi \pm\left(\frac{\pi}{6}\right)\)
- B \(2 n \pi \pm\left(\frac{\pi}{3}\right)\)
- C \(n \pi+1(-1)^n\left(\frac{\pi}{3}\right)\)
- D \(n \pi \pm\left(\frac{\pi}{3}\right)\)
Answer & Solution
Correct Answer
(B) \(2 n \pi \pm\left(\frac{\pi}{3}\right)\)
Step-by-step Solution
Detailed explanation
Given that, terms \(\frac{1}{6} \sin \theta, \cos \theta\) and \(\tan \theta\) are in GP.…
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