AP EAMCET · Maths · Permutation Combination
A number lock has 3 rings and each ring has 8 digits. Total number of different ways in which 3 rings can be rotated is
- A \(3^8\)
- B \(8^3\)
- C \(3 \times 8\)
- D \({ }^8 P_3\)
Answer & Solution
Correct Answer
(B) \(8^3\)
Step-by-step Solution
Detailed explanation
Since, it is given that a lock has 3 rings and each ring has 8 digits, so each ring can be rotated in 8 ways, therefore total number of different ways in which 3 rings can be rotated is \(8 \times 8 \times 8=8^3\). Hence, option (b) is correct.
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