AP EAMCET · Maths · Probability
In a manufacturing company, three machines A, B and C respectively produce \(20 \%, 30 \%\) and \(50 \%\) of the total product. The defective products from A, B and C are respectively 5\%, \(3 \%\) and \(2 \%\). If an article produced by the company is selected at random and is found to be defective, then the probability that it is produced by machine \(B\) is
- A \(\frac{10}{29}\)
- B \(\frac{8}{29}\)
- C \(\frac{9}{29}\)
- D \(\frac{11}{29}\)
Answer & Solution
Correct Answer
(C) \(\frac{9}{29}\)
Step-by-step Solution
Detailed explanation
Let events, Production by machine \(\mathrm{A}=E_1\) Production by machine \(\mathrm{B}=E_2\) Production by Machine \(\mathrm{C}=E_3\) and let defective production \(=E\) Then, probabilities of production by machine \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) respectively is…
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