AP EAMCET · Chemistry · Structure of Atom
The work functions of \(\mathrm{Ag}, \mathrm{Mg}, \mathrm{K}\) and \(\mathrm{Na}\) respectively in \(\mathrm{eV}\) are \(4.3,3.7,2.25,2.30\). When an electromagnetic radiation of wavelength of \(300 \mathrm{~nm}\) is allowed to fall on these metal surface, the number of metals from which the electrons are ejected is
\[
\left(\mathbf{e V}=1.6022 \times 10^{-19} \mathrm{~J}\right)
\]
- A 4
- B 3
- C 2
- D 5
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Energy of EM wave used \[ \begin{aligned} & E=\frac{h c}{\lambda}=\frac{6.6 \times 10^{-34} \times 3 \times 10^8}{300 \times 10^{-9}} \\ & E=0.066 \times 10^{-17}=6.6 \times 10^{-19} \mathrm{~J} \end{aligned} \] Metals surface which have work function less than or equal to…
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