AP EAMCET · Chemistry · Thermodynamics (C)
The enthalpy of formation \(\left(\Delta \mathrm{H}_f\right)\) of methanol, formaldehyde and water are \(-239,-116\) and \(-286 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The enthalpy change for the oxidation of methanol to formaldehyde and water in \(\mathrm{kJ}\) is
- A -136
- B -173
- C 163
- D -163
Answer & Solution
Correct Answer
(D) -163
Step-by-step Solution
Detailed explanation
Given \(\Delta H_f\) for \(\mathrm{CH}_3 \mathrm{OH}=-239 \mathrm{~kJ} \mathrm{~mol}^{-1}\) \(\Delta H_f\) of \(\mathrm{H} . \mathrm{CHO}=-116 \mathrm{~kJ} \mathrm{~mol}^{-1}\) \(\Delta H_f\) of \(\mathrm{H}_2 \mathrm{O}=-286 \mathrm{~kJ} \mathrm{~mol}^{-1}\) Required relation:…
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