AP EAMCET · Chemistry · Structure of Atom

The element with outer electronic configuration $(n - 1) d^{2} n s^{2}$ , where $n = 4$ , would belong to

A $2^{n d}$ period, $2^{n d}$ group
B $4^{th}$ period, $4^{th}$ group
C $4^{th}$ period, $2^{nd}$ group
D $2^{n d}$ period, $4^{th}$ group

Verified Solution

Answer & Solution

Correct Answer

(B) $4^{th}$ period, $4^{th}$ group

Step-by-step Solution

Detailed explanation

We know that the general configuration of d-block element is (n−1)d1−10ns1−2 where n is the period number. Here given electronic configuration is (n-1)d2ns2, where n=4. So, here the period number will be 4. For d-block elements the group number can be found by…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The element with outer electronic configuration (n-1)d2ns2, where n=4, would belong to

Step-by-step Solution

The element with outer electronic configuration $(n - 1) d^{2} n s^{2}$ , where $n = 4$ , would belong to