AP EAMCET · Chemistry · Structure of Atom
The graph between variation of probability density, \(\psi^2(r)\) and distance of the electron from the nucleus, \(r\) is shown below. This represents
- A \(1 s-\) orbital
- B \(2 s\) - orbital
- C \(3 s-\) orbital
- D \(2 p\)-orbital
Answer & Solution
Correct Answer
(B) \(2 s\) - orbital
Step-by-step Solution
Detailed explanation
The region where probability density function, \(\psi_{(\mathrm{r})}^2\) reduces to zero is called nodel surfaces or simply nodes ns orbital has \((\mathrm{n}-1)\) nodes. Given graph has one node. So it should be 2 s -orbital. General formula for calculating radial nodes in…
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\begin{gathered}
\mathrm{H}_2 \mathrm{O}(g)+\mathrm{C}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_2(g) ; \\
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