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AP EAMCET · Maths · Ellipse

If the eccentric angles of the extremeties of a focal chord (other than the major axis) of the ellipse \(\frac{x^2}{25}+\frac{y^2}{9}=1\) are \(\alpha\) and \(\beta\) then \(\frac{\cot \left(\frac{\alpha}{2}\right)}{\tan \left(\frac{\beta}{2}\right)}=\)

  1. A \(\frac{4}{3}\)
  2. B -9
  3. C 9
  4. D \(\frac{4}{5}\)
Verified Solution

Answer & Solution

Correct Answer

(B) -9

Step-by-step Solution

Detailed explanation

\( a^2=25, b^2=9 \) \( e = \sqrt{1 - \frac{b^2}{a^2}} = \sqrt{1 - \frac{9}{25}} = \frac{4}{5} \) \( \tan \left(\frac{\alpha}{2}\right) \tan \left(\frac{\beta}{2}\right) = \frac{e-1}{e+1} = \frac{\frac{4}{5}-1}{\frac{4}{5}+1} = -\frac{1}{9} \)…