AP EAMCET · PHYSICS · Electromagnetic Induction
When a current of 4 mA passes through an inductor, if the flux linked with it is \(32 \times 10^{-6} \mathrm{~T} \mathrm{~m}^2\), then the energy stored in the inductor is
- A \(64 \times 10^{-9} \mathrm{~J}\)
- B \(32 \times 10^{-9} \mathrm{~J}\)
- C \(128 \times 10^{-9} \mathrm{~J}\)
- D \(96 \times 10^{-9} \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(64 \times 10^{-9} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(U = \frac{1}{2} \Phi I\) \(U = \frac{1}{2} (32 \times 10^{-6} \mathrm{~Wb}) (4 \times 10^{-3} \mathrm{~A})\) \(U = 64 \times 10^{-9} \mathrm{~J}\)
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