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AP EAMCET · Chemistry · Structure of Atom

Match the following species with the correct number of electrons present in them:
Species Number of Electrons
 (iBe2+ (a) 0
 (iiH+ (b) 10
 (iiiNa+ (c) 2
 (ivMg+ (d) 11
  (e) 4
 

  1. A (i-d),(i i-c),(i i-b),(i v-a)
  2. B (i-a),(i i-b),(i i i-c),(i v-d)
  3. C (i-e),(i i-d),(i i-a),(i v-c)
  4. D (i-c),(i i-a),(i i i-b),(i v-d)
Verified Solution

Answer & Solution

Correct Answer

(D) (i-c),(i i-a),(i i i-b),(i v-d)

Step-by-step Solution

Detailed explanation

We know that the number of electrons is equal to the atomic number of element in neutral state. Atomic number of beryllium is 4 but Be2+ can be formed by losing the two electrons so remaining electrons in Be2+ will be 4-2 = 2. Similarly, the number of electrons in H+…