AP EAMCET · Chemistry · Structure of Atom
Maximum number of electrons possible with spin quantum number \(+\frac{1}{2}\) with principal quantum number \(\mathrm{n}=4\) in an atom is
- A \(16\)
- B \(9\)
- C \(4\)
- D \(25\)
Answer & Solution
Correct Answer
(A) \(16\)
Step-by-step Solution
Detailed explanation
Maximum number of electrons \(=2 n^2=2 \times 4 \times 4=32(\) when \(n=4)\) Half of the electrons have \(\left(+\frac{1}{2}\right)\) spin, i.e., 16
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