AP EAMCET · Chemistry · Chemical Kinetics
The rate constant of a first order reaction is \(3.46 \times 10^{-2} \mathrm{~s}^{-1}\) at 298 K . What is the rate constant of the reaction at 350 K if its activation energy is \(50.1 \mathrm{~kJ} \mathrm{~mol}^{-1} ?(\mathrm{R}=8.314 \mathrm{~J}\) \(\mathrm{K}^{-1} \mathrm{~mol}^{-1}\) )
\((\log 2=0.3010)\)
- A \(0.592 \mathrm{~s}^{-1}\)
- B \(0.692 \mathrm{~s}^{-1}\)
- C \(0.792 \mathrm{~s}^{-1}\)
- D \(0.892 \mathrm{~s}^{-1}\)
Answer & Solution
Correct Answer
(B) \(0.692 \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{K}_1=3.46 \times 10^{-2} \\ & \mathrm{~T}_1=298 \mathrm{~K} \\ & \mathrm{~K}_2=? \\ & \mathrm{~T}_2=350 \mathrm{~K} \\ & \mathrm{E}_{\mathrm{a}}=50.1 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}…
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