AP EAMCET · Maths · Definite Integration
\(\int_0^{\frac{\pi}{4}} \frac{\sin x+\cos x}{3+\sin 2 x} d x\) is equal to
- A \(\frac{1}{2} \log 3\)
- B \(\log 2\)
- C \(\log 3\)
- D \(\frac {1}{4} \log 3\)
Answer & Solution
Correct Answer
(D) \(\frac {1}{4} \log 3\)
Step-by-step Solution
Detailed explanation
Let \(I=\int_0^{\pi / 4} \frac{\sin x+\cos x}{3+\sin 2 x} d x\) Put \(\sin x-\cos x=t\) \((\sin x+\cos x) d x=d t\) Limits:…
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