AP EAMCET · Chemistry · Solutions
At \(300 \mathrm{~K}, 6 \mathrm{~g}\) of urea was dissolved in 500 mL of water. What is the osmotic pressure (in atm) of resultant solution?
\(\begin{aligned}
& \left(R=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right) \\
& (\mathrm{C}=12 ; \mathrm{N}=14 ; O=16 ; \mathrm{H}=1)
\end{aligned}\)
- A 0.492
- B 2.46
- C 4.92
- D 49.2
Answer & Solution
Correct Answer
(C) 4.92
Step-by-step Solution
Detailed explanation
Osmotic pressure \((\pi)=\) CRT Given, Weight of urea \(=6 \mathrm{~g}\) Molecular weight of urea \(\therefore \quad\) Number of mole of urea \(=\frac{\text { Weight }}{\text { Molecular weight }}\) \(\Rightarrow \frac{6}{60}=0.1 \mathrm{~mole}\)…
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