AP EAMCET · Chemistry · p Block Elements (Group 13 & 14)

Match the following.

List - $I$ Reaction List - $II$ Catalyst

$(A)$ $N_{2} (g) + 3 H_{2} (g) ⟶ 2 {NH}_{3} (g)$ $(I)$ $Ni$

$(B)$ $2 H_{2} (g) + O_{2} (g) ⟶ 2 H_{2} O (l)$ $(II)$ $Pt$

$(C)$ $CO (g) + 3 H_{2} (g) ⟶ {CH}_{4} (g) + H_{2} O (g)$ $(III)$ $ZnO - {Cr}_{2} O_{3}$

$(D)$ $CO (g) + 2 H_{2} (g) ⟶ {CH}_{3} OH (g)$ $(IV)$ $Fe$

The correct answer is:

A

$A$ $B$ $C$ $D$

$III$ $II$ $I$ $IV$
B

$A$ $B$ $C$ $D$

$IV$ $III$ $II$ $I$
C

$A$ $B$ $C$ $D$

$IV$ $II$ $I$ $III$
D

$A$ $B$ $C$ $D$

$IV$ $I$ $III$ $II$

Verified Solution

Answer & Solution

Correct Answer

(C)

$A$	$B$	$C$	$D$
$IV$	$II$	$I$	$III$

Step-by-step Solution

Detailed explanation

The catalyst for the reactions is, List-I List-II N2(g)+3H2(g)→2NH3(g) In Haber's process N2and H2 are combined in 1:3 ratio at 200 atm pressure and high temperature 400-450°C. Fe 2H2(g)+O2(g)→2H2O(l) On passing Oxygen over Hydrogen adsorbed platinum,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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List - $I$ Reaction		List - $II$ Catalyst
$(A)$	$N_{2} (g) + 3 H_{2} (g) ⟶ 2 {NH}_{3} (g)$	$(I)$	$Ni$
$(B)$	$2 H_{2} (g) + O_{2} (g) ⟶ 2 H_{2} O (l)$	$(II)$	$Pt$
$(C)$	$CO (g) + 3 H_{2} (g) ⟶ {CH}_{4} (g) + H_{2} O (g)$	$(III)$	$ZnO - {Cr}_{2} O_{3}$
$(D)$	$CO (g) + 2 H_{2} (g) ⟶ {CH}_{3} OH (g)$	$(IV)$	$Fe$

Match the following. List - I Reaction List - II Catalyst (A) N2(g)+3H2(g)⟶2NH3(g) (I) Ni (B) 2H2(g)+O2(g)⟶2H2O(l) (II) Pt (C) CO(g)+3H2(g)⟶CH4(g)+H2O(g) (III) ZnO-Cr2O3 (D) CO(g)+2H2(g)⟶CH3OH(g) (IV) Fe The correct answer is:

Step-by-step Solution