AP EAMCET · PHYSICS · Electromagnetic Induction
The thermo emf of a hypothetical thermocouple varies with the temperature \(\theta\) of hot junction as \(E=a \theta+b \theta^2\) in volts, where the ratio \(a / b\) is \(700^{\circ} \mathrm{C}\). If the cold junction is kept at \(0^{\circ} \mathrm{C}\), then the neutral temperature is
- A \(700^{\circ} \mathrm{C}\)
- B \(1400^{\circ} \mathrm{C}\)
- C \(390^{\circ} \mathrm{C}\)
- D None of these
Answer & Solution
Correct Answer
(D) None of these
Step-by-step Solution
Detailed explanation
Given, \(E=a \theta+b \theta^2\) \(\begin{aligned} \therefore \quad p & =\frac{d E}{d \theta}=\frac{d}{d \theta}\left(a \theta+b \theta^2\right) \\ & =a+2 b \theta \end{aligned}\) At \(\quad \theta=T_n, p=0\) \(\Rightarrow \quad T_n=-\frac{a}{2 b}=-350^{\circ} \mathrm{C}\) No…
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