AP EAMCET · Chemistry · Solutions
At \(293 \mathrm{~K}\), the Henry law constant in water for \(\mathrm{N}_2\) and \(\mathrm{O}_2\) are \(76.48 \mathrm{k}\) bar and \(34.86 \mathrm{k}\) bar respectively. What is the ratio of mole fractions of \(\mathrm{N}_2\) and \(\mathrm{O}_2\) in water?
(Assume partial pressures of \(\mathrm{N}_2\) and \(\mathrm{O}_2\) same at \(293 \mathrm{~K}\) )
- A 2.19
- B 0.95
- C 0.6
- D 0.45
Answer & Solution
Correct Answer
(D) 0.45
Step-by-step Solution
Detailed explanation
According to Henry's law :- \[ \mathrm{P}=\mathrm{xK}_{\mathrm{H}} \] For \(\mathrm{N}_2\) :- \(\mathrm{P}_{\mathrm{N}_2}=\mathrm{x}_{\mathrm{N}_2} \mathrm{~K}_{\mathrm{H}}\left(\mathrm{N}_2\right)\) For \(\mathrm{O}_2\) :-…
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