AP EAMCET · Chemistry · Thermodynamics (C)
At \(300 \mathrm{~K}\) the enthalpy change for the following reaction is \(-2800 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- A \(-2802.49\)
- B \(-2800.00\)
- C \(-2814.94\)
- D \(+2802.49\)
Answer & Solution
Correct Answer
(B) \(-2800.00\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} \Delta \mathrm{H}=\Delta \mathrm{U}+\mathrm{P} \Delta \mathrm{V}=\Delta \mathrm{U}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT} \\ & \Rightarrow \Delta \mathrm{U}=\Delta \mathrm{H}-\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}=(-2800)-(0 \times 0.082 \times…
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