AP EAMCET · Chemistry · Solid State
Analysis shows that nickel oxide has the formula \(\mathrm{Ni}_{0.98} \mathrm{O}_{1.00}\). The fractions \(\mathrm{Ni}^{2+}\) and \(\mathrm{Ni}^{3+}\) ions in the crystal are ......
- A \(\mathrm{Ni}^{2+}=98 \%\) and \(\mathrm{Ni}^{3+}=2 \%\)
- B \(\mathrm{Ni}^{2+}=2 \%\) and \(\mathrm{Ni}^{3+}=98 \%\)
- C \(\mathrm{Ni}^{2+}=4 \%\) and \(\mathrm{Ni}^{3+}=96 \%\)
- D \(\mathrm{Ni}^{2+}=96 \%\) and \(\mathrm{Ni}^{3+}=4 \%\)
Answer & Solution
Correct Answer
(D) \(\mathrm{Ni}^{2+}=96 \%\) and \(\mathrm{Ni}^{3+}=4 \%\)
Step-by-step Solution
Detailed explanation
It is given that, nickel oxide has the formula as \(\mathrm{Ni}_{0.98} \mathrm{O}_{1.00}\). As per the formula, there are \(98 \mathrm{Ni}\) ions for 100 oxide ions. Out of \(98 \mathrm{Ni}\) ions, let \(x\) ions be in +2 oxidation state. \((98-x)\) ions will be in +3 oxidation…
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