AP EAMCET · PHYSICS · Gravitation
An object is thrown directly away from the surface of the earth with an initial speed \(v\). The object reaches upto a height of \(\frac{4}{5} R_E\) from earth's surface, where \(R_E\) is radius of the earth. If the escape velocity of the object is \(v_E\) then the value of \(\frac{v}{v_E}\) is
- A \(4 / 3\)
- B \(3 / 4\)
- C \(2 / 3\)
- D \(4 / 5\)
Answer & Solution
Correct Answer
(C) \(2 / 3\)
Step-by-step Solution
Detailed explanation
We know that, maximum height attained by a projectile projected with velocity \(v\). \[ h=\frac{v^2 R_E}{2 g R_E-v^2} \] But given, \(h=\frac{4}{5} R_E\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from PHYSICS
- A gody is projected from the ground at an angle of \(\tan ^{-1}\left(\frac{8}{7}\right)\) with the horizontal. The ratio of the maximum height attained by it to its range isAP EAMCET 2018 Easy
- Pure silicon at 300 K has equal electron and hole concentration of \(1.5 \times 10^{16} \mathrm{~m}^{-3}\). If the hole concentration increases to \(3 \times 10^{22} \mathrm{~m}^{-3}\), then electron concentration in the silicon isAP EAMCET 2024 Easy
- Young's modulus for perfectly rigid body isAP EAMCET 2020 Easy
- A steady current flows in a long wire. It is bent into a circular loop of one turn and the magnetic field at the centre of the coil is \(B\). If the same wire is bent into a circular loop of \(n\) turns, the magnetic field at the centre of the coil isAP EAMCET 2014 Medium
- A microscope consists of an objective of focal length \(1.9 \mathrm{~cm}\) and eye piece of focal length \(5 \mathrm{~cm}\). The two lenses are kept at a distance of \(10.5 \mathrm{~cm}\). If the image is to be formed at the least distance of distinct vision, the distance at which the object is to be placed before the objective is (least distance of distinct vision is \(25 \mathrm{~cm}\) )AP EAMCET 2013 Easy
- The displacement of a particle of mass 2 g executing simple harmonic motion is \(x=8 \cos \left(50 t+\frac{\pi}{12}\right) m\), where \(t\) is time in second. The maximum kinetic energy of the particle isAP EAMCET 2024 Easy
More PYQs from AP EAMCET
- Let the point L lying in the first quadrant be one end of a latus rectum of the ellipse \(\frac{x^2}{4}+\frac{y^2}{3}=1\). Let \(P\) and \(Q\) be the points where the normal drawn at \(\mathrm{L}\) to this given ellipse meets the major axis and the minor axis. Then the distance between \(\mathrm{P}\) and \(\mathrm{Q}\) isAP EAMCET 2023 Hard
- The domain of the function \(f(x)=\sqrt{\log _e\left(\frac{1}{x^2-4 x+4}\right)}+\sin ^{-1}\left(x^2-2\right)\) isAP EAMCET 2025 Medium
- If \(a\) and \(b\) are arbitrary constants, then the differential equation having \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) as its general solution isAP EAMCET 2018 Easy
- If \(x\) is numerically so small so that \(x^2\) and higher powers of \(x\) can be neglected, then \(\left(1+\frac{2 x}{3}\right)^{3 / 2} \cdot(32+5 x)^{-1 / 5}\) is approximately equal toAP EAMCET 2009 Easy
- In a triangle ABC, if \(\sin \frac{\mathrm{A}}{2}=\frac{1}{4} \sqrt{\frac{3}{5}}, \mathrm{a}=2, \mathrm{c}=5\) and b is an integer, then the area (in sq. units) of triangle ABC isAP EAMCET 2025 Medium
- At , dinitrogen tetroxide is fifty percent dissociated. Find its standard free energy change at this temperature and one atmosphere. [ Given: ]AP EAMCET 2021 Medium