AP EAMCET · Chemistry · Carboxylic Acid Derivatives
Arrange the products I, II, III from the following reactions in decreasing order of their acid strength.
A)
\(\xrightarrow[\text { (ii) } \mathrm{H}_3 \mathrm{O}^{+}]{\text {(i) } \mathrm{KMnO}_4 / \mathrm{OH}^{-}} \mathrm{I}\)
B) \(\mathrm{CH}_3 \mathrm{COOH} \xrightarrow[\text { (ii) } \mathrm{H}_2 \mathrm{O}]{\text { (i) } \mathrm{Br}_2 / \operatorname{red~P}} \mathrm{II}\)
C)
\(\xrightarrow[\substack{\text { (ii) } \mathrm{CO}_2 / \text { dry ether } \\ \text { (iii) } \mathrm{H}_3 \mathrm{O}^{+}}]{\text {(i) } \mathrm{Mg} / \text { dry ether }}\)
- A III \(>\) II \(>\) I
- B III \(>\) I \(>\) II
- C \(\mathrm{II}>\mathrm{I}>\mathrm{III}\)
- D \(\mathrm{I}>\mathrm{II}>\mathrm{III}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{II}>\mathrm{I}>\mathrm{III}\)
Step-by-step Solution
Detailed explanation
I: \( \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH} \) II: \( \mathrm{BrCH}_2 \mathrm{COOH} \) III: \( \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH} \) \( \mathrm{pKa}(\mathrm{II}) \approx 2.9 \) \( \mathrm{pKa}(\mathrm{I}) = \mathrm{pKa}(\mathrm{III}) \approx 4.2 \) Decreasing order:…
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