AP EAMCET · Maths · Indefinite Integration
\(\begin{aligned}
& \frac{4 x^2+5}{(x-2)^4}=\frac{A}{(x-2)}+\frac{B}{(X-2)^2}+\frac{C}{(X-2)^3}+\frac{D}{(X-2)^4} \text { then } \\
& \sqrt{\frac{A}{C}+\frac{B}{C}+\frac{D}{C}}=
\end{aligned}\)
- A \(\frac{\sqrt{29}}{4}\)
- B \(\frac{\sqrt{23}}{4}\)
- C \(\frac{5}{4}\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{5}{4}\)
Step-by-step Solution
Detailed explanation
\(\frac{4 x^2+5}{(x-2)^4}=\frac{A}{x-2}+\frac{B}{(x-2)^2}+\frac{C}{(x-2)^3}+\frac{D}{(x-2)^4}\) \(\Rightarrow A(x-2)^3+B(x-2)^2+C(x-2)+D=4 x^2+5\) If \(x=2 \Rightarrow D=21\) Co-efficient of \(x^3, A=0\) Constant term, \(4 B-2 C+21=5 \Rightarrow 4 B-2 C=-16\) Co-efficient of…
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