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AP EAMCET · Maths · Permutation Combination

The number of arrangements of the letters of the word ARRANGEMENT in which two Es' do not occur adjacently is

  1. A \(\frac{9}{8}(10) !\)
  2. B \(\frac{9}{4}(10) !\)
  3. C \(\frac{9}{16}(10) !\)
  4. D \(\frac{9}{32}(10)!\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{9}{16}(10) !\)

Step-by-step Solution

Detailed explanation

Total arrangements \(=\frac{\lfloor 11}{\lfloor 2 \cdot 2 \cdot|2 \cdot| 2}\) Number of arrangement in which two E occur together \(=\frac{10}{2 \cdot 2 \cdot 2 \cdot 2}\) \(=\frac{10.9}{16}=\frac{9}{16}\lfloor 10\)