AP EAMCET · Maths · Parabola
The normal drawn at a point \((2,-4)\) on the parabola \(y^2=8 x\) cuts again the same parabola at \((\alpha, \beta)\) then \(\alpha+\beta=\)
- A \(8\)
- B \(16\)
- C \(24\)
- D \(30\)
Answer & Solution
Correct Answer
(D) \(30\)
Step-by-step Solution
Detailed explanation
Given the parabola, \(y^2=8 x \Rightarrow a=2\) Now, given a point on \(y^2=8 x\) is \((2,-4)\) \(\Rightarrow(2,-4)=\left(a t^2, 2 a t\right) \Rightarrow(2,-4)=\left(2 t^2, 4 t\right) \Rightarrow t=-1\) Since, normal drawn at \((2,-4)\) again meet at \((\alpha, \beta)\) So,…
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