AP EAMCET · Chemistry · Coordination Compounds
Arrange the following in order of increasing number of unpaired electrons in them
i. \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}\)
ii. \(\left[\mathrm{MnCl}_6\right]^{3-}\)
iii. \(\left[\mathrm{FeF}_6\right]^{3-}\)
iv. \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}\)
- A i, iv, ii, iii
- B iv, i, iii, ii
- C iv, i, ii, ii
- D i, iv, iii, ii
Answer & Solution
Correct Answer
(C) iv, i, ii, ii
Step-by-step Solution
Detailed explanation
(i) \(\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}:-\) \(\mathrm{Fe}\) is in +3 state and \(\mathrm{CN}^{-}\)is a strong-field ligand. Thus, \(\mathrm{Fe}^{3+}=[\mathrm{Ar}] 3 \mathrm{~d}^5\) or Thus, there is only one unpaired electron. (ii)…
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