AP EAMCET · Chemistry · Solid State
Iron exhibits bcc structure at room temperature. Above \(500^{\circ} \mathrm{C}\), it transforms to fcc structure. Find the ratio of the density of iron at room temperature to that at \(500^{\circ} \mathrm{C}\). (Assume the atomic radii and the molar mass of iron remain constant even with variation in temperature)
- A \(3 \sqrt{3}: 4 \sqrt{2}\)
- B \(\sqrt{3}: \sqrt{2}\)
- C \(\sqrt{2}: \sqrt{3}\)
- D \(10: 92\)
Answer & Solution
Correct Answer
(A) \(3 \sqrt{3}: 4 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
We know, Density, \(d=Z M / a^3 N_0\) For bcc unit cell, \(Z=2, a=\frac{4}{\sqrt{3}} r\) \[ d_{\mathrm{bcc}}=\frac{2 M}{\left(\frac{4}{\sqrt{3}} r\right)^3 N_0} \] For fcc unit cell, \(\quad Z=4, a=\frac{4}{\sqrt{2}} r\)…
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