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AP EAMCET · Chemistry · Structure of Atom

The difference in radii between fourth and third Bohr orbits of \(\mathrm{He}^{+}\)(in m) is

  1. A \(2.64 \times 10^{-10}\)
  2. B \(1.85 \times 10^{-12}\)
  3. C \(1.85 \times 10^{-10}\)
  4. D \(1.85 \times 10^{-9}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1.85 \times 10^{-10}\)

Step-by-step Solution

Detailed explanation

Bohr radii \(\left(\mathrm{r}_{\mathrm{n}}\right)=52.9 \times \frac{\mathrm{n}^2}{\mathrm{Z}} \mathrm{pm}\) radii of fourth orbit of \(\mathrm{He}^{+}=52.9 \times \frac{(4)^2}{2}\) radii of third orbit of \(\mathrm{He}^{+}=52.9 \times \frac{(3)^2}{2}\) difference of radii…