AP EAMCET · PHYSICS · Nuclear Physics
The energy released when one nucleus of \({ }_{92} \mathrm{U}^{235}\) undergoes fission is \(188 \mathrm{MeV}\). The energy released when \(100 \mathrm{~g}\) of \({ }_{92} \mathrm{U}^{235}\) undergoes fission is
- A \(3.55 \times 10^{12} \mathrm{~J}\)
- B \(7.71 \times 10^{12} \mathrm{~J}\)
- C \(3.55 \times 10^{13} \mathrm{~J}\)
- D \(7.71 \times 10^{13} \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(7.71 \times 10^{12} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
Given, energy released, \(E_0=188 \mathrm{MeV}\) per nucleus fission and mass, \(m=100 \mathrm{gm}\) As number of nucleus in \(100 \mathrm{gm}\) of \({ }_{92} \mathrm{U}^{235}\) \(N=\frac{100}{M} \times N_A\) where, \(N_A=\) Avogadro number and \(M=\) molecular mass…
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