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JEE Mains · Maths · STD 11 - 12. limits

यदि \(\lim _{x \rightarrow 0} \frac{\alpha e^x+\beta e^{-x}+\gamma \sin x}{x \sin ^2 x}=\frac{2}{3}\),है, जहाँ \(\alpha, \beta, \gamma \in R\) हैं, तो निम्न में से कौनसा सही नहीं है ?

  1. A \(\alpha^{2}+\beta^{2}+\gamma^{2}=6\)
  2. B \(\alpha \beta+\beta \gamma+\gamma \alpha+1=0\)
  3. C \(\alpha \beta^{2}+\beta \gamma^{2}+\gamma \alpha^{2}+3=0\)
  4. D \(\alpha^{2}-\beta^{2}+\gamma^{2}=4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\alpha \beta^{2}+\beta \gamma^{2}+\gamma \alpha^{2}+3=0\)

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Detailed explanation

\(\lim _{x \rightarrow 0} \frac{\alpha\left(1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots\right)+\beta\left(1-x+\frac{x^{2}}{2 !}-\frac{x^{3}}{3 !}+\ldots\right)+\gamma\left(x-\frac{x^{3}}{3 !}+\ldots\right)}{x^{3}}\) constant terms should be zero \(a+\beta=0\) coeff of \(x\)…
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