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JEE Mains · Maths · STD 12 - 9. differential equations

यदि \(\frac{d y}{d x}+\frac{2^{x-y}\left(2^y-1\right)}{2^x-1}=0, x, y > 0, y(1)=1\) है,तब \(y (2)\) बराबर होगा।

  1. A \(2+\log _{2} 3\)
  2. B \(2+\log _{2} 2\)
  3. C \(2-\log _{2} 3\)
  4. D \(2-\log _{2} 3\)
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Answer & Solution

Correct Answer

(D) \(2-\log _{2} 3\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}+\frac{2^{x-y}\left(2^{y}-1\right)}{2^{x}-1}=0,\) \(x , y >0, y (1)=1, y (2)=?\) \(\frac{d y}{d x}=-\frac{2^{x}\left(2^{y}-1\right)}{2^{y}\left(2^{x}-1\right)}\) \(\int \frac{2^{y}}{2^{y}-1} d y=-\int \frac{2^{x}}{2^{x}-1} d x\)…
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