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JEE Mains · Maths · STD 12 - 11. three dimension geometry

यदि बिंदु \(P ( a , 4,2), a > 0\) से रेखा \(\frac{ x +1}{2}=\frac{ y -3}{3}=\frac{ z -1}{-1}\) पर डाले गए लंब की लंबाई \(2 \sqrt{6}\) इकाई है तथा इस रेखा में बिंदु \(P\) का प्रतिबिंब \(Q \left(\alpha_1, \alpha_2, \alpha_3\right)\) है, तो \(a +\sum \limits_{ i =1}^3 \alpha_{ i }\) बराबर है :

  1. A \(7\)
  2. B \(8\)
  3. C \(12\)
  4. D \(14\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(8\)

Step-by-step Solution

Detailed explanation

\((2 \lambda-1-a) 2+(3 \lambda-1) 3+(-\lambda-1)(-1)=0\) \(4 \lambda-2-2 a+9 \lambda-3+\lambda+1=0\) \(14 \lambda-4-2 a =0\) \(7 \lambda-2-a=0\) and, \((2 \lambda-1-a)^{2}+(3 \lambda-1)^{2}+(\lambda+1)^{2}=24\) \(5 \lambda-1)^{2}+(3 \lambda-1)^{2}+(\lambda+1)^{2}=24\)…
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