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JEE Mains · Maths · STD 11 - 7. binomial theoram

यदि \(\left(1+a x+b x^{2}\right)(1-2 x)^{18}\) के \(x\) की घातों में प्रसार में \(x^{3}\) तथा \(x^{4}\), दोनों के गुणांक शून्य हैं, तो \((a, b)\) बराबर है :

  1. A (\(14\),\(\frac{{272}}{3}\))
  2. B (\(16\),\(\frac{{272}}{3}\))
  3. C (\(16\),\(\frac{{251}}{3}\))
  4. D (\(14\),\(\frac{{251}}{3}\))
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Answer & Solution

Correct Answer

(B) (\(16\),\(\frac{{272}}{3}\))

Step-by-step Solution

Detailed explanation

In the expansion of \(\left(1+a x+b x^{2}\right)(1-2 x)^{18},\) Coefficient of \(x^{3}\) in \(\left(1+a x+b x^{2}\right)(1-2 x)^{18}\) \(=\) Coefficient of \(x^{3}\) in \((1-2 x)^{18}\) \({+\text { Coefficient of } x^{2} \text { in a }(1-2 x)^{\text {18 }}}\)…
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