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JEE Mains · Maths · STD 12 - 11. three dimension geometry

वृत्त \(x^2+y^2=1, z=0\) के एक बिंदु से समतल \(2 x+3 y+z=6\) पर डाले गए लंब का पाद निम्न में से किस वक्र पर है ?

  1. A \((6 x+5 y-12)^{2}+4(3 x+7 y-8)^{2}=1\), \(z=6-2 x-3 y\)
  2. B \((5 x+6 y-12)^{2}+4(3 x+5 y-9)^{2}=1\), \(z=6-2 x-3 y\)
  3. C \((6 x+5 y-14)^{2}+9(3 x+5 y-7)^{2}=1\), \(z=6-2 x-3 y\)
  4. D \((5 x+6 y-14)^{2}+9(3 x+7 y-8)^{2}=1\), \(z=6-2 x-3 y\)
Verified Solution

Answer & Solution

Correct Answer

(B) \((5 x+6 y-12)^{2}+4(3 x+5 y-9)^{2}=1\), \(z=6-2 x-3 y\)

Step-by-step Solution

Detailed explanation

\(\frac{ h -\cos \theta}{2}=\frac{ k -\sin \theta}{3}=\frac{ w -0}{1}\) \(=\frac{-1(2 \cos \theta+3 \sin \theta-6)}{14}\) \(h =\cos \frac{-2(2 \cos \theta+3 \sin \theta-6)}{14}\) \(=\frac{10 \cos \theta-6 \sin \theta+12}{14}\)…
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