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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

माना समीकरण \(\mathrm{x}^7+3 \mathrm{x}^5-13 \mathrm{x}^3-15 \mathrm{x}=0\) के मूल \(\alpha_1, \alpha_2, \ldots, \alpha_7\) हैं तथा \(\left|\alpha_1\right| \geq\left|\alpha_2\right| \geq \ldots \geq\left|\alpha_7\right|\) हैं तो \(\alpha_1 \alpha_2-\alpha_3 \alpha_4+\alpha_5 \alpha_6\) बराबर है____________. 

  1. A \(9\)
  2. B \(8\)
  3. C \(7\)
  4. D \(6\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(9\)

Step-by-step Solution

Detailed explanation

Given equation can be rearranged as \(x\left(x^6+3 x^4-13 x^2-15\right)=0\) clearly \(x=0\) is one of the root and other part can be observed by replacing \(x ^2= t\) from which we have \(\quad t^3+3 t^2-13 t-15=0\) \(\Rightarrow \quad( t -3)\left( t ^2+6 t +5\right)=0\) So,…
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