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JEE Mains · Maths · STD 11 - 4.1 complex nubers

माना सम्मिश्र संख्याएँ \(z = a + ib , b \neq 0\), समीकरण \(z ^2=\overline{ z } \cdot 2^{1-| z |}\) को संतुष्ट करती हैं। तब \(n \in N\) का निम्नतम मान, जिसके लिए \(z ^{ n }=( z +1)^{ n }\) है, बराबर है \(........\)

  1. A \(0\)
  2. B \(6\)
  3. C \(5\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(6\)

Step-by-step Solution

Detailed explanation

\(\left|z^{2}\right|=|\bar{z}| \cdot 2^{1-|z|} \Rightarrow|z|=1\) \(z ^{2}=\overline{ z } \Rightarrow z ^{3}=1 \therefore z =\omega\) or \(\omega^{2}\) \(\omega^{ n }=(1+\omega)^{ n }=\left(-\omega^{2}\right)^{ n }\) Least natural value of \(n\) is \(6.\)
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