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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

माना सभी फलनों \(f:[0,1] \rightarrow R\), जो कि \([0,1]\) पर संतत हैं तथा \((0,1)\) पर अवकलनीय हैं, का समुच्चय \(S\) हैं। तो \(S\) में प्रत्येक \(f\) के लिए \(f\) पर निर्भर एक \(c \in(0,1)\) का अस्तित्व इस प्रकार है कि

  1. A \(|f(c)-f(1)|<(1-c)\left|f^{\prime}(c)\right|\)
  2. B \(|f(c)-f(1)|<\left|f^{\prime}(c)\right|\)
  3. C \(|f(c)+f(1)|<(1+c)\left|f^{\prime}(c)\right|\)
  4. D \(\frac{f(1)-f(\mathrm{c})}{1-\mathrm{c}}=f^{\prime}(\mathrm{a})\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(|f(c)-f(1)|<\left|f^{\prime}(c)\right|\)

Step-by-step Solution

Detailed explanation

option \((1),(2),(3)\) are incorrect for \(f(x)=\) constant and option ( 4) is incorrect \(\frac{f(1)-f(\mathrm{c})}{1-\mathrm{c}}=f^{\prime}(\mathrm{a})\) where \(\mathrm{c}<\mathrm{a}<1\) (use LMVT) Also for \(f(x)=x^{2}\)
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