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JEE Mains · Maths · STD 12 - 9. differential equations

माना \(F :[3,5] \rightarrow R (3,5)\) पर दो बार अवकलनीय फलन है, जिसके लिए \(F ( x )= e ^{- x } \int_{3}^{ x }\left(3 t ^{2}+2 t +4 F ^{\prime}( t )\right) dt\) है। यदि \(F ^{\prime}(4)=\frac{\alpha e ^{\beta}-224}{\left( e ^{\beta}-4\right)^{2}}\) है, तो \(\alpha+\beta\) बराबर है..............।

  1. A \(8\)
  2. B \(16\)
  3. C \(48\)
  4. D \(32\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(16\)

Step-by-step Solution

Detailed explanation

\(F(3)=0\) \(\mathrm{e}^{\mathrm{x}} \mathrm{F}(\mathrm{x})=\int_{3}^{\mathrm{x}}\left(3 \mathrm{t}^{2}+2 \mathrm{t}+4 \mathrm{~F}^{\prime}(\mathrm{t})\right) \,\mathrm{dt}\) \(e^{x} F(x)=e^{x} F^{\prime}(x)=3 x^{2}+2 x+4 F^{\prime}(x)\)…
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