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JEE Mains · Maths · STD 12 - 9. differential equations

माना अवकल समीकरण \(\left(1-x^2\right) d y=\left[x y+\left(x^3+2\right) \sqrt{3\left(1-x^2\right)}\right] d x\), \(-1<\mathrm{x}<1, \mathrm{y}(0)=0\) का हल \(\mathrm{y}=\mathrm{y}(\mathrm{x})\) है। यदि \(\mathrm{y}\left(\frac{1}{2}\right)=\frac{m}{n}, m\) तथा \(n\) सह-अभाज्य संख्याऐं है, तो \(\mathrm{m}+\mathrm{n}\) = ...........

  1. A \(91\)
  2. B \(92\)
  3. C \(97\)
  4. D \(77\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(97\)

Step-by-step Solution

Detailed explanation

\( \frac{d y}{d x}-\frac{x y}{1-x^2}=\frac{\left(x^3+2\right) \sqrt{3\left(1-x^2\right)}}{1-x^2} \) \( I F=e^{-\int \frac{x}{1-x^2} d x}=e^{+\frac{1}{2} \ln \left(1-x^2\right)}=\sqrt{1-x^2} \) \( y \sqrt{1-x^2}=\sqrt{3} \int\left(x^3+2\right) d x \)…
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