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JEE Mains · Maths · STD 12 - 10. vector algebra

माना \(\overrightarrow{\mathrm{a}}=-\hat{\mathrm{i}}-\hat{\mathrm{j}}+\hat{\mathrm{k}}, \overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{b}}=1\) तथा \(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}=\hat{\mathrm{i}}-\hat{\mathrm{j}}\) तो \(\overrightarrow{\mathrm{a}}-6 \overrightarrow{\mathrm{b}}\) बराबर है -

  1. A \(3(\hat{i}-\hat{j}-\hat{k})\)
  2. B \(3(\hat{i}+\hat{j}+\hat{k})\)
  3. C \(3(\hat{i}-\hat{j}+\hat{k})\)
  4. D \(3(\hat{i}+\hat{j}-\hat{k})\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3(\hat{i}+\hat{j}+\hat{k})\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ a } \times \overrightarrow{ b }=(\hat{ i }-\hat{ j })\) Taking cross product with \(\overrightarrow{ a }\) \(\Rightarrow \quad \vec{a} \times(\vec{a} \times \vec{b})=\vec{a} \times(\hat{i}-\hat{j})\)…
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