ExamBro
ExamBro
JEE Mains · Maths · STD 12 - 5. continuity and differentiation

मान लीजिए \(\quad f:(-\infty, \infty)-\{0\} \rightarrow R\) एक अवकलनीय फलन है इस प्रकार कि \(f^{\prime}(1)=\lim _{a \rightarrow \infty} a^2 f\left(\frac{1}{a}\right)\). तब \(\lim _{a \rightarrow \infty} \frac{a(a+1)}{2} \tan ^{-1}\left(\frac{1}{a}\right)+a^2-2 \log _e a\) = ...........

  1. A  \(\frac{3}{2}+\frac{\pi}{4}\)
  2. B  \(\frac{3}{8}+\frac{\pi}{4}\)
  3. C  \(\frac{5}{2}+\frac{\pi}{8}\)
  4. D  \(\frac{3}{4}+\frac{\pi}{8}\)
Verified Solution

Answer & Solution

Correct Answer

(C)  \(\frac{5}{2}+\frac{\pi}{8}\)

Step-by-step Solution

Detailed explanation

\( f:(-\infty, \infty)-\{0\} \rightarrow R \) \( f^{\prime}(1)=\lim _{a \rightarrow \infty} a^2 f\left(\frac{1}{a}\right) \) \( \lim _{a \rightarrow \infty} \frac{a(a+1)}{2} \tan ^{-1}\left(\frac{1}{a}\right)+a^2-2 \ln (a) \)…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app