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JEE Mains · Maths · STD 11 - 10.1 circle and system of circle

बिन्दु \((0,1)\) से होकर जाने वाले तथा परवलय \(y = x ^{2}\) को बिन्दु \((2,4)\) पर स्पर्श करने वाले वृत का केन्द्र है

  1. A \(\left(\frac{3}{10}, \frac{16}{5}\right)\)
  2. B \(\left(\frac{-16}{5}, \frac{53}{10}\right)\)
  3. C \(\left(\frac{6}{5}, \frac{53}{10}\right)\)
  4. D \(\left(\frac{-53}{10}, \frac{16}{5}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\left(\frac{-16}{5}, \frac{53}{10}\right)\)

Step-by-step Solution

Detailed explanation

\(y=x^{2}\) \(\left.\frac{d y}{d x}\right|_{P}=4\) \((y-4)=4(x-2)\) \(4 x-y-4=0\) Circle \(:(x-2)^{2}+(y-4)^{2}+\lambda(4 x-y-4)=0\) passes through (0,1) \(4+9+\lambda(-5)=0 \Rightarrow \lambda=\frac{13}{5}\) Circle \(: x^{2}+y^{2}+x(4 \lambda-4)+y(-\lambda-8)+(20-4 \lambda)=0\)…
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